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Stella [2.4K]
4 years ago
14

1 Which points show the translation (x, y) + (x-1 y+4)?

Mathematics
1 answer:
NemiM [27]4 years ago
7 0

Answer:

I will answer if you insert a picture

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Someone please help me will give BRAILIEST!!!!!
marishachu [46]
B. x > 70
 is the correct answer
3 0
4 years ago
Read 2 more answers
Easy 6th grade math! Please help!
Pie

Answer:

Step-by-step explanation 10 + 2.50d = 850

David starts with $10 and each day he earns $2.50. The d represents a variable and can be any number.

To find d you must solve the equation.

10 + 2.50d = 850

2.50d = 840 (subtract 10 from 850)

d = 336 (divide 840 by 2.50)

It will take David 336 days to save $850.

3 0
4 years ago
Guys look at the pic of the park and read the question I need this ASAP WITH ALL STEPS the choices are
Alik [6]

Answer:

A. 821.5 Square Yards

Step-by-step explanation:

30 x 30= 900

900 is the area for the whole park

To find the pool area you need to do pi times Radius squared

so 3.14 x 5 x 5

That equals 78.5 for the pool area.

So to find the grass area you need to subtract the pool area from the park

900 - 78.5 = 821.5 square yards!

5 0
3 years ago
Hey guys what is this type of equation/ question called 1 < x < 30
dimulka [17.4K]

Answer:

2,3,4,5,6,7,8,9,10,...29

Step-by-step explanation:

6 0
3 years ago
For the following exercises, determine whether the relation is a function.
elixir [45]

Answer:

The given relation $\{(a, b),(c, d),(e, d)\}$ is a function.

Step-by-step explanation:

A relation $\{(a, b),(c, d),(e, d)\}$ is given.

It is required to determine whether the given relation is a function.

To determine whether the given function is a relation, identify the domain and range and then check whether the given relation is a function.

Step 1 of 1

The given relation is {(a, b),(c, d),(e, d)}.

The set of the first components of each ordered pair is called the domain.

From the relation, the domain is {a, c, e}.

The set of the second components of each ordered the range.

From the relation, the range is {b, d, d}.

The given relation is a function. But it is not a one-to-one function.

7 0
2 years ago
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