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Anestetic [448]
3 years ago
11

Find the perimeter of the image below

Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer:

46

Step-by-step explanation:

vovikov84 [41]3 years ago
5 0

Answer:

26.1

Step-by-step explanation:

Took the same test lol

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The topology taxi company charges 2.30 for the first quarter of a mile and 0.40 for each additional fifth of a mile. Find a line
Bond [772]

Answer:

Is this a multiple choice?

Step-by-step explanation:

3 0
3 years ago
Find the value of 2m for m= 1,2 and 3
Nonamiya [84]

Use the substitution method

Answers:

2m

2(1)

= 2

2(2)

= 4

2(3)

= 6

7 0
3 years ago
Read 2 more answers
What is two 2/3÷1 1/6
babunello [35]

Answer:

0.57142857142

Step-by-step explanation:

6 0
3 years ago
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Solve the given inequality. Describe the solution set using the set-builder or interval notation. Then, graph the solution set o
Korolek [52]

Answer:

B

Step-by-step explanation:

10(10m+6)<=12        

100m+60<=12       Distributive Property

100m     <=12-60

100m    <=-48

     m    <=-48/100

     m    <=-.48

This says values for m that are less than or equal to -.48

-.48 is between -1 and 0 so the answer is B

6 0
3 years ago
Read 2 more answers
Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would
maxonik [38]

Answer:  b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e.  135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137  ,

since  135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146  

since  135.8< 146 < 155.9

So , it is usual.

d. 155  

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0
3 years ago
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