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Anestetic [448]
3 years ago
11

Find the perimeter of the image below

Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer:

46

Step-by-step explanation:

vovikov84 [41]3 years ago
5 0

Answer:

26.1

Step-by-step explanation:

Took the same test lol

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How many solutions are there to the equation below?
Scrat [10]

Answer:

B

Step-by-step explanation:

6x + 30 + 4x = 10(x+3)

10x + 30 = 10x + 30

0 = 0

3 0
3 years ago
Which statement describes the translation of y=-1/2(x-2)^2-2 from standard position?
Masteriza [31]
Y = x^2 is the parent function.
y = (x - 2)^2 would translate 2 units to the right
y = (x - 2)^2 - 2 would translate 2 units to the right and also 2 units down
y = - (1/2) (x - 2)^2 - 2
would reflect the parabola upside down, and also make it wider
6 0
3 years ago
Logic gates I have no clue how to do this
kobusy [5.1K]

Answer: It is the 3rd option. But I am not sure if it is correct- pls tell me back if the answer was correct!

6 0
3 years ago
10
Mekhanik [1.2K]

Answer:

ithink 8470 the answer

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Which of the following is NOT a linear factor of the polynomial function?
Natalija [7]

Answer:

Among the four choices, (x + 5) is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let a denote some constant. A linear factor of the form (x - a) is a factor of a polynomial f(x) if and only if f(a) = 0 (that is: replacing all x in the polynomial f(x) \! with the constant a\! would give this polynomial a value of 0.)

For example, in the second linear factor (x - 2), the value of the constant is a = 2. Verify that the value of f(2) is indeed 0. (In other words, replacing all x in the polynomial f(x) \! with the constant 2 should give this polynomial a value of 0\!.)

\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}.

Hence, (x - 2) is indeed a linear factor of polynomial f(x).

Similarly, it could be verified that (x - 5) and (x + 2) are also linear factors of this polynomial function.

Rewrite the first linear factor (x + 5) in the form (x - a) for some constant a: (x + 5) = (x - (-5)), where a = -5.

Calculate the value of f(5).

\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}.

f(5) \ne 0 implies that (x - (-5)) (which is equivalent to (x + 5)) isn't a linear factor of this polynomial function.

3 0
3 years ago
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