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sasho [114]
2 years ago
10

Help help I need to find the height of a cylinder helppp The volume is 1215 The radius is9

Mathematics
1 answer:
Naddika [18.5K]2 years ago
8 0

Answer:

15

Step-by-step explanation:

Its pretty simple, u need to learn this.

The solution is volume divided by area of circle.

Area of circle is π times radius square.

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2 years ago
The mathematics section of a standardized college entrance exam had a mean of 19.8 and an SD of 5.1 for a recent year. Assume th
Fudgin [204]

Answer:

a) 0.84% of students scored over 32

b) 29.12% of students scored under 17​

c) 70.04% of students scored between 17 and 32.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 19.8, \sigma = 5.1

a) About what percent of students scored over 32​?

This is 1 subtracted by the pvalue of Z when X = 32. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{32 - 19.8}{5.1}

Z = 2.39

Z = 2.39 has a pvalue of 0.9916

1 - 0.9916 = 0.0084

So 0.84% of students scored over 32

​b) About what percent of students scored under 17​?

This is the pvalue of Z when X = 17. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 19.8}{5.1}

Z = -0.55

Z = -0.55 has a pvalue of 0.2912

So 29.12% of students scored under 17​

c) About what percent of students scored between 17 and 32​?

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 12. So

X = 32

Z = \frac{X - \mu}{\sigma}

Z = \frac{32 - 19.8}{5.1}

Z = 2.39

Z = 2.39 has a pvalue of 0.9916

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 19.8}{5.1}

Z = -0.55

Z = -0.55 has a pvalue of 0.2912

0.9916 - 0.2912 = 0.7004

70.04% of students scored between 17 and 32.

5 0
2 years ago
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