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sasho [114]
2 years ago
10

Help help I need to find the height of a cylinder helppp The volume is 1215 The radius is9

Mathematics
1 answer:
Naddika [18.5K]2 years ago
8 0

Answer:

15

Step-by-step explanation:

Its pretty simple, u need to learn this.

The solution is volume divided by area of circle.

Area of circle is π times radius square.

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Write an expression for “5 more pounds than joe”
LenKa [72]

Answer:

x+5

Step-by-step explanation:

Since you don't know how much Joe weighs, you can express his weight as x. Then, you add on 5 because you have 5 more lbs than joe (which is x).

3 0
3 years ago
if the unit price for oranges is $0.26 per pound and Jim pays $2.08 for oranges, how many puns of oranges does he buy? A) 4.5 po
Nata [24]
Hey there!

If the price per orange is $.26 and we want to know how many oranges he bought and we have our total, we can set o equal to how many oranges he got and set up an algebraic equation:

0.26o = 2.08

We multiply .26 by o because o is how many oranges he bought and that's what we're solving for- so we multiply by the unit price.

To isolate o, we divide both sides by .26 to get:

The answer is C- Jim bought 8 oranges.

Hope this helps!
4 0
2 years ago
Read 2 more answers
How to solve this problem im not getting a good answer
kow [346]
Well, you have to simplify the bottom part to be able to answer it as a whole number. Hope this helps. 
7 0
3 years ago
Read 2 more answers
1. Write 6 x 104 in standard form. <br> O 600 <br>O 6,000 <br>O 60.000<br> O 600.000​
BlackZzzverrR [31]

the answer is 60,000

For Connexus students:

1.  6,0000

2. 2,300

3. 9.68 x 10 to the 5th power

4. 8.6 x 10 to the 3rd power

5. the number of places to move the decimal point to the right

6 0
2 years ago
Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
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