Hey there! I'm happy to help!
To find the area of a circle, you square the radius and then multiply by pi (3.14 in our case).
The radius is half of the diameter.
12.6/2=6.3
We square this.
6.3²=39.69
We multiply by 3.14
39.69×3.14=124.6266
We round to the nearest hundredth, giving us an area of 124.63 in².
Now you can find the area of a circle! Have a wonderful day! :D
The <em><u>correct answers</u></em> are:
B- x + y ≤ 10
; and D- x ≥ 4
Explanation:
The illusionist needs at least 4 female volunteers. This means he could use 4 or more; this means x, the number of female volunteers, is greater than or equal to 4:
x ≥ 4
The total of number of volunteers needed is up to 10. This means the illusionist can use 10 or fewer people; this means the total is less than or equal to 10.
The number of female volunteers is x and the number of male volunteers is y; together they create the expression x+y. This gives us
x+y ≤ 10
1. incorrect
2. correct
3. incorrect (?)
Answer:
that answer is 7 is bigger then 1.9
Step-by-step explanation:
so 7 is a whole and 1.9 is a decimal

Step-by-step explanation:
Given functions are:

h(x) is the product of g(x) and f(x)

Combining like terms

Hence,

Keywords: Functions, product
Learn more about functions at:
#LearnwithBrainly