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3 years ago

Write an equation of the line that passes through (0,-5) and (-5,-5)

Mathematics

1 answer:

nikitadnepr [17]3 years ago

6 0

-5- -5=0 which leads to slope of zero. (0, -5) is the y-intercept so it is Y= -5

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1/4(x+2)+4=12 <br> x=? Help idk

Gnoma [55]

$\frac{1}{4}(x+2)+4=12$

$\frac{1}{4}(x+2)=8$

$x+2=32$

$x=30$

5 0

3 years ago

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Plz help! Gonna need to turn it soon

Veseljchak [2.6K]

Answer:

C - 13*

Step-by-step explanation:

3 0

3 years ago

Part B if the height of each prism is 10 Cm what is the surface area prism

Evgen [1.6K]

Answer:

Prism A:

$Area = 288cm^2$

Prism B:

$Area =250cm^2$

Step-by-step explanation:

Given

See attachment for prisms

$Height(h) = 10cm$

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

$Area = 2 * A_b + (a + b + c) * h$

Where

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

and

$s = \frac{a + b + c}{2}$

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

$a = 8; b =6; c =10$

So, we have:

$s = \frac{a + b + c}{2}$

$s = \frac{8 + 6 + 10}{2}$

$s = \frac{24}{2}$

$s = 12$

Also:

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

$A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}$

$A_b = \sqrt{576}$

$A_b = 24$

So:

$Area = 2 * A_b + (a + b + c) * h$

$Area = 2 * 24 + (8 + 6 + 10) * 10$

$Area = 288cm^2$

Prism B is a rectangular prism. So, the area is calculated as:

$Area = 2 * (ab + bh + ah)$

From the attachment

$a = b = 5$

$h =10$

So:

$Area =2 * (5 * 5 + 5 * 10 + 5 * 10)$

$Area =250cm^2$

7 0

2 years ago

Which one is bigger 10/10 or 6/6

nasty-shy [4]

Answer:

Both are <u>equal</u> to each other.

Step-by-step explanation:

$\frac{10}{10} = 1$

$\frac{6}{6} = 1$

7 0

3 years ago

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The graph of a line passes through the points (0,-2) and (6,0). what is the equation of the line?

nirvana33 [79]

Answer:

y = 1/3x - 2

Step-by-step explanation:

We are asked to find the equation of a line with two points

Step1: find the slope

m = (y_2 - y_1)/(x_2 - x_1)

( 0 , -2) (6 , 0)

x_1 = 0

y_1 = -2

x_2 = 6

y_2 = 0

Insert the values

m = ( 0 - (-2)/ (6 - 0)

m = ( 0 + 2)/(6 - 0)

m = 2/6

m = (2/2)/(6/2)

m = 1/3

Step 2 : substitute m into the equation of line

y = mx + c

y = intercept y

m = slope

x = intercept x

c = intercept

y = 1/3x + c

Step 3: sub any of the two points

Let's pick ( 6 ,0)

x = 6

y = 0

Insert the values into

y = 1/3x + c

0 = 1/3(6) + c

0 = 1*6/3 + c

0 = 6/3 + c

0 = 2 + c

c = 0 - 2

c = -2

Sub c = -2

y = 1/3x - 2

The equation of the line is

y = 1/3x - 2

5 0

3 years ago