<h3>
The constant of proportionality is k = 5</h3>
For direct proportion equations, you divide the y value over its corresponding x value to get the value of k.
For example, the point (x,y) = (2,10) is on the diagonal line. So k = y/x = 10/2 = 5.
Another example: the point (x,y) = (6, 30) is also on the same diagonal line, so k = y/x = 30/6 = 5 is the same result as before.
You can use any point on the diagonal line as long as it is not (0,0). This is because division by zero is not allowed.
side note: the direct proportion equation y = k*x becomes y = 5*x which is the graph of that diagonal line. The slope is m = 5, the y intercept is b = 0. All direct proportion graphs go through the origin as shown in the diagram.
Answer:
y+7=5/4(x-8)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-7)=5/4(x-8)
y+7=5/4(x-8)
First multiply 11 with 9 to get 99 and then 11 with d to get 11d
thus the answer is 99+11d.
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
