(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution
In this question, the first information that we get is that Kayla spent half of her weekly allowance in clothes. On cleaning the oven Kayla gets $4. Finally Kayla is left with $12.
Let us assume that the weekly allowance of Kayla = x
Amount of allowance saved after buying clothes = x/2
Then we can go for the equation
x/2 + 4 = 12
x + (4 * 2) = 12 * 2
x + 8 = 24
x = 24 -8
= 16
So we can now see that the weekly allowance of Kayla is $16
Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:
Rationalize the denominator by multiplying both numerator and denominator by √10:
Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):
So 1 USD is 2.89 RON
That means...
177 ÷ 2.89 = 61.24USD
