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3 years ago

If anyone has done shop, I really need help with this.

Mathematics

1 answer:

GalinKa [24]3 years ago

3 0

Answer:

1.B

1.2.C

1.3.A

1.4.B

1.5.B

second number 1. C

2.B

3.A

4.C

Step-by-step explanation:

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Another easy question pls answer

timama [110]

Always true, 90+90=180

6 0

2 years ago

Read 2 more answers

Create an equation that represents a parabola that opens upward

algol13

For a parabola that opens upward, it must be a quadratic equation whose coefficient of x2 is a positive number.

So, I'll say x2+5x+6.

8 0

3 years ago

Rectangle A measures 9 in by 3 in in rectangle B is a scaled copy of rectangle A. all measurements

taurus [48]

Answer:
3
Step-by-step explanation:
2 +2 =4 -1 is 3

5 0

3 years ago

The tee for the sixth hole on a golf course is 305 yards from the tee. On that hole, Marsha hooked her ball to the left, as sket

EleoNora [17]

Answer:

Correct answer is option D. 96.4 yd.

Step-by-step explanation:

Please refer to the attached figure for labeling of the given diagram.

ABC is a triangle with the following labeling:

A is the hole, B is the Tee and C is the point where the ball is.

Sides are labeled as:

$a =255\ yd\\c = 305\ yd\\\angle B =17^\circ$

To find:

Side $b = ?$

Solution:

Here, we have one angle and two sides . Third side of the triangle is to be found opposite to the given angle.

We can use cosine formula here to find the value of the unknown side.

$cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}$

Putting all the values:

$cos 17 = \dfrac{255^{2}+305^{2}-b^{2}}{2\times 255\times 305}\\\Rightarrow 0.956 = \dfrac{65025+93025-b^{2}}{155550}\\\Rightarrow 148753.2= 158050-b^{2}\\\Rightarrow b^{2}= 158050-148753.2\\\Rightarrow b^{2}= 9296.795\\\Rightarrow b= 96.42\ yd$

So, the distance between the Ball and hole is 96.42 yd

Correct answer is option D. 96.4 yd.

8 0

2 years ago

Can you see an easy way to work out the value of <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%201%5E3%20%2B%202%5E3%20%2B%203%5E

Lina20 [59]

We have the sum of cubes identity

$a^3 + b^3 = (a + b) (a^2 - ab + b^2)$

and observing that 1 + 4 = 2 + 3, we have

$1^3 + 4^3 = (1 + 4) (1^2 - 4 + 4^2) = 5 \times 13$

and

$2^3 + 3^3 = (2 + 3) (2^2 - 6 + 3^2) = 5 \times 7$

Then

$\sqrt{1^3+2^3+3^3+4^3+5^3} = \sqrt{5\times13 + 5\times7 + 5\times5^2} = \sqrt{5 \times (20 + 25)} \\\\ ~~~~~~~~ = \sqrt{5^2 \times (4 + 5)} = \sqrt{5^2\times9} = \sqrt{5^2\times3^2} = 5\times3 = \boxed{15}$

Alternatively, we have the well-known sum of cubes formula

$\displaystyle \sum_{i=1}^n i^3 = \frac{n^2(n+1)^2}4$

The sum under the square root is this sum with $n=5$ . Then

$1^3+2^3+3^3+4^3+5^3 = \dfrac{5^2\times6^2}4 = 225 = 15^2$

and so the square root again reduces to 15.

5 0

1 year ago