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3 years ago

If anyone has done shop, I really need help with this.

Mathematics

1 answer:

GalinKa [24]3 years ago

3 0

Answer:

1.B

1.2.C

1.3.A

1.4.B

1.5.B

second number 1. C

2.B

3.A

4.C

Step-by-step explanation:

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Whatdkdjfdjjfksakknshaja

trapecia [35]

i think you have to multiply those. thats it

8 0

3 years ago

1. Four bags of chips cost $6. 1. What is the cost per bag? 2. At this rate, how much will 7 bags of chips cost?

77julia77 [94]

Answer:

$1.50 dollars per bag and at that rate it would be $7.50 for 6 bags of chips

Step-by-step explanation:

8 0

2 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

2 years ago

Choose the correct way to read 75.09

MakcuM [25]

75.09 = seventy- five and nine-hundredths

5 0

2 years ago

Read 2 more answers

1) Simplify the following expressions: a) sin²108° + sin² 18°

abruzzese [7]

Note that

108° = 90° + 18°

sin(108°) = sin(90° + 18°) = sin(90°) cos(18°) + cos(90°) sin(18°) = cos(18°)

Then

sin²(108°) + sin²(18°) = cos²(18°) + sin²(18°) = 1

by the Pythagorean identity.

8 0

2 years ago