Answer:
(a)
Step-by-step explanation:
x + x(xx)
Put the value of x = 2 in the above expression we get,
2 + 2(22)
= 2 + 2(2 × 2)
= 2 + 2(4)
= 2 + 8
= 10
Answer: (a)
We have the <span> Trigonometric Identities : </span>secx = 1/cosx; (sinx)^2 + (cosx)^2 = 1;
Then, 1 / (1-secx) = 1 / ( 1 - 1/cosx) = 1 / [(cosx - 1)/cosx] = cosx /
(cosx - 1 ) ;
Similar, 1 / (1+secx) = cosx / (1 + cosx) ;
cosx / (cosx - 1) + cosx / (1 + cosx) = [cosx(1 + cosx) + cosx (cosx - 1)] / [ (cosx - 1)(cox + 1)] =[cosx( 1 + cosx + cosx - 1 )] / [ (cosx - 1)(cox + 1)] = 2(cosx)^2 / [(cosx)^2 - (sinx)^2] = <span> 2(cosx)^2 / (-1) = - 2(cosx)^2;
</span>
Answer:
H = 60(3/4)^x
Step-by-step explanation:
After each bounce, the height it reach is 3/4 the previous one.
Let the height of nth bounce be denoted as h_n and the first bounce is h_1.
We are given that h_1 = 60 cm. Following the rule in the problem, we get:
h_2 = (3/4)h_1 = (3/4)60
h_3 = (3/4)h_2 = (3/4)*(3/4)60 = 60(3/4)^2
h_4 = (3/4)h_3 = (3/4)*60(3/4)^2= 60(3/4)^3
We see that h_n = 60(3/4)^n is the formula for the height for the nth bounce. Therefore, H = 60(3/4)^x is the answer.
I hope this helps! :)
Answer: Yes, No
Step-by-step explanation:
1st table is linear because the slope is always constant.
Second is not linear, but rather exponential.