Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
limits, if they exist. (If an answer does not exist, enter DNE.) (a) lim x → 2 [ f ( x ) + 5 g ( x ) ] limx→2[f(x)+5g(x)] (b) lim x → 2 [ g ( x ) ] 3 limx→2[g(x)]3 (c) lim x → 2 √ f ( x ) limx→2f(x) (d) lim x → 2 4 f ( x ) g ( x ) limx→24f(x)g(x) (e) lim x → 2 g ( x ) h ( x ) limx→2g(x)h(x) (f) lim x → 2 g ( x ) h ( x ) f ( x ) limx→2g(x)h(x)f(x)