Given the relationship T^2 = A^3, to compare the values of the orbital periods of X and Y, it would be easier to assign values. Since the Planet Y's distance A is twice that of Planet X's distance A, this can be shown below:
For Planet X (where A = 2):
T^2 = 2^3
T = 2.828
For Planet Y (where A = 4)
T^2 = 4^3
T = 8
Therefore, planet Y's orbital period is larger by (8/2.828) = 2.83 times.
Answer:
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Step-by-step explanation:
Hello :
<span>h(x) = 6x² − 60x + 147= (x² -2(30)x+30²)-30²+147
</span>h(x) = (x-30)²-753 .....(vertex form)
<span>the axis of symmetry is the line of equation : x=30</span>
6(x - 3) - 10 = 2(x + 3)
6x - 18 - 10 = 2x + 6
6x - 28 = 2x + 6
add 28 to both sides of the equation
6x = 2x + 34
subtract 2x from both sides of the equation
4x = 34
divide 4 from both sides of the equation
x = 8.5
