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Korolek [52]
3 years ago
13

Please help! show work if you can

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

C

Step-by-step explanation:

i did test please comment if its wrong

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Please help with the math problem below
Nesterboy [21]
Answer: C. Subtraction Property of Inequality
6 0
3 years ago
Find the perimeter of the triangle with these vertices. (−5,4), (3,1,) ,( −5,1) Give an exact answer (not a decimal approximatio
scoundrel [369]

Answer:

The answer to your question is Perimeter = 11 + \sqrt{73}

Step-by-step explanation:

Data

P (-5, 4)

Q (3, 1)

R (-5, 1)

Process

Calculate the distance between the points and sum up the results

a)

dPQ = \sqrt{(-5 - 3)^{2} + (4 - 1)^{2}}

dPQ = \sqrt{(-8)^{2} + 3^{2}}

dPQ = \sqrt{64 + 9}

dPQ = \sqrt{73}

dQR = \sqrt{(-5 - 3)^{2} + (1 - 1)^{2}}

dQR = \sqrt{8^{2}}

dQR = 8

dPR = \sqrt{(-5 + 5)^{2}+ (1 - 4)^{2}}

dPR = \sqrt{3^{2}}

dPR = 3

b)

Perimeter = \sqrt{73} + 8 + 3

Perimeter = 11 + \sqrt{73}

3 0
3 years ago
Brain to first correct answer
scZoUnD [109]
<h3>Answer:  40%</h3>

Explanation:

Add up the numbers shown: 10+11+3+1 = 25

Then we divide like so: 10/25 = 0.40 = 40%

8 0
3 years ago
Read 2 more answers
Calculate the area of quadrilateral ABCD.<br> State the units of your answer.
cluponka [151]

Answer:

158.76 cm²

Step-by-step explanation:

Quadrilateral ABCD is composed of 2 right triangles

Construct the line BD, then

Δ ABD and Δ BCD are the 2 right triangles.

The area (A) of a triangle is calculated using

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Δ ABD with b = 18 and h = 7.5

A = \frac{1}{2} × 18 × 7.5 = 9 × 7.5 = 67.5 cm²

Δ BCD with b = 15.6 and h = 11.7

A = \frac{1}{2} × 15.6 × 11.7 = 7.8 × 11.7 = 91.26 cm²

Thus

area of ABCD = 67.5 + 91.26 = 158.76 cm²

3 0
3 years ago
How do I solve this?
Korolek [52]
<span><span>   (<span>x−8</span>)</span>2</span><span>=<span><span>(<span>x+<span>−8</span></span>)</span><span>(<span>x+<span>−8</span></span>)</span></span></span><span>=<span><span><span><span><span>(x)</span><span>(x)</span></span>+<span><span>(x)</span><span>(<span>−8</span>)</span></span></span>+<span><span>(<span>−8</span>)</span><span>(x)</span></span></span>+<span><span>(<span>−8</span>)</span><span>(<span>−8</span>)</span></span></span></span><span>=<span><span><span><span>x2</span>−<span>8x</span></span>−<span>8x</span></span>+64</span></span><span>=<span><span><span>x2</span>−<span>16x</span></span>+<span>64

</span></span></span><span>(x−8)2=x2−82Step 1: Simplify both sides of the equation.x2−16x+64=x2−64Step 2: Subtract x^2 from both sides.x2−16x+64−x2=x2−64−x2−16x+64=−64Step 3: Subtract 64 from both sides.−16x+64−64=−64−64−16x=−128Step 4: Divide both sides by -16.−16x−16=−128−16x=8</span>
6 0
3 years ago
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