Answer:
When 2x^2 - 10x - 3 is plugged into the quadratic equation, the resulting zeroes are x = (5 + sqrt(31))/2 and (5 - sqrt(31))/2. Hope this helps!
Step-by-step explanation:
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<span>3x+4=y+5, then y+5=3x+4
It is called: reflexive property
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<span>x = y and y = 10, then x = 10
It is called: equality substitution property
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Hello,
As h(x) is a bijection,
range(h(x))=dom(h^(-1)(x))={0,1,2,3}
Answer C
The x intrercepts is where the function crosses the x axis; In other words, it is where the output of the function is 0.
In a quadratic, you can start by factoring, if it’s unable to be factored then use the quadratic formula. Also, it is good to use the discriminate.
D= Discrimminate
D>0 2 real solutions
D=0 1 real solution
D<0 2 imaginary solutions.
The discrimminate is the equation/expression under the radical of the quadratic formula. With this formula, it’s not factorable. Using the discriminate it is also seen, as you’ll get a negative in the square root. This is imagenary because you cannot take the root of a negative value, which is why “i” is used to represent the square root of negative one.