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ankoles [38]
3 years ago
15

What is the positive root of the equation x 2 + 5x = 150? a0

Mathematics
1 answer:
Radda [10]3 years ago
5 0
Solution for x^2+5x=150 equation:
<span>Simplifying x2 + 5x = 150 Reorder the terms: 5x + x2 = 150 Solving 5x + x2 = 150 Solving for variable 'x'. Reorder the terms: -150 + 5x + x2 = 150 + -150 Combine like terms: 150 + -150 = 0 -150 + 5x + x2 = 0 Factor a trinomial. (-15 + -1x)(10 + -1x) = 0 Subproblem 1Set the factor '(-15 + -1x)' equal to zero and attempt to solve: Simplifying -15 + -1x = 0 Solving -15 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '15' to each side of the equation. -15 + 15 + -1x = 0 + 15 Combine like terms: -15 + 15 = 0 0 + -1x = 0 + 15 -1x = 0 + 15 Combine like terms: 0 + 15 = 15 -1x = 15 Divide each side by '-1'. x = -15 Simplifying x = -15 Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10Solutionx = {-15, 10}</span>
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We know: The sum of the measures of the angles of a triangle is equal 180°.

We have: m∠A =65°, m∠B =  (3x - 10)° and m∠C = (2x)°.

The equation:

65 + (3x - 10) + 2x = 180

(3x + 2x) + (65 - 10) = 180

5x + 55 = 180        <em>subtract 55 from both sides</em>

5x = 125          <em>divide both sides by 5</em>

x = 25

m∠B =  (3x - 10)° → m∠B =  (3 · 25 - 10)° = (75 - 10)° = 65°

m∠C = (2x)° → m∠C = (2 · 25)° = 50°

<h3>Answer: x = 25, m∠B = 65°, m∠C = 50°</h3>
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sides of right angle triangle follows Pythagoras theorem

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if you check, option 3 follow this. so answer is option 3

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Answer:

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