Question

What is the positive root of the equation x 2 + 5x = 150? a0

Answer 1

Solution for x^2+5x=150 equation:
Simplifying x2 + 5x = 150 Reorder the terms: 5x + x2 = 150 Solving 5x + x2 = 150 Solving for variable 'x'. Reorder the terms: -150 + 5x + x2 = 150 + -150 Combine like terms: 150 + -150 = 0 -150 + 5x + x2 = 0 Factor a trinomial. (-15 + -1x)(10 + -1x) = 0 Subproblem 1Set the factor '(-15 + -1x)' equal to zero and attempt to solve: Simplifying -15 + -1x = 0 Solving -15 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '15' to each side of the equation. -15 + 15 + -1x = 0 + 15 Combine like terms: -15 + 15 = 0 0 + -1x = 0 + 15 -1x = 0 + 15 Combine like terms: 0 + 15 = 15 -1x = 15 Divide each side by '-1'. x = -15 Simplifying x = -15 Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10Solutionx = {-15, 10}