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3 years ago

Write in the equation for the slope intercept form and please no links or I will report you

Mathematics

1 answer:

Rashid [163]3 years ago

3 0

Answer:

y = 3/2x + 8

Step-by-step explanation:

using points (-2,5) and (0,8),

we find slope, by using rise/run aka the y's/x's. so 8-5/0--2= 3/2 for slope. (8,0) is an intercept, so b out y=mx +b has been found!

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Write the Recursive Rule for the sequence:

skad [1K]

A formula is recursive if it expresses the term $a_n$ in terms of the previous one(s) $a_{n-1},\ a_{n-2},\ \ldots,\ a_1$

In this case, every term is 7 more than the previous one, so the formula for $a_n$ will only involve $a_{n-1}$ :

$a_n = a_{n-1} + 7$

In fact, this formula is simply saying: for every index $n$ , the term with that index is 7 more than the term before.

Also, we have to specify the starting point (otherwise we would go backwards indefinitely), so the complete recursive formula is

$a_n = a_{n-1} + 7,\quad a_1 = 2$

which means: start with 2 and generate every other term by adding 7 to the previous one.

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3 years ago

A polynomial divided by a polynomial is a polynomial. always, sometimes, or never true?

Artemon [7]

I think it is always true. I am not sure but I hope I'm right

3 0

3 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

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velikii [3]

Answer:

8, 0, -8, -12

Step-by-step explanation:

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3 years ago

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sweet-ann [11.9K]

Answer:

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Step-by-step explanation:

1 and 1 = 2 1 and 1 =2 1+1=2 1+1=2

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3 years ago