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ohaa [14]
3 years ago
15

Write in the equation for the slope intercept form and please no links or I will report you

Mathematics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

y = 3/2x + 8

Step-by-step explanation:

using points (-2,5) and (0,8),

we find slope, by using rise/run aka the y's/x's. so 8-5/0--2= 3/2 for slope. (8,0) is an intercept, so b out y=mx +b has been found!

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Which statement about g(x) = x^2 - 576 is true?
Zina [86]

Answer:

The second option.

Step-by-step explanation:

Let's see if this will work.

(x+24)(x-24)

Let's open the brackets

x^2 - 24x +24x - 576

= x^2 - 576

Please give brainliest

I hope you understand. If you don't. Please, leave a comment below.

7 0
3 years ago
What is the distance between (-3,2) and (3,0)
KATRIN_1 [288]

Answer:

right 6 and down 2

Step-by-step explanation:

I used a graphing calculator

4 0
3 years ago
Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?
lilavasa [31]
We have the following function:
 f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
 We note that the function depends on x because it is f (x).
 However, there is no variable x in the function.
 Therefore we can assume that the function is constant, since:
 a = constant
 b = constant
 Therefore, the degree of the function is zero
 Answer:
 
The function is zero degree.
7 0
3 years ago
How to write 12/5 as a mixed number
Marat540 [252]

Answer:

2 2/5

Step-by-step explanation:

divide 12 into 5 you get 2.4

2.4 is the same as 2 4/10 which can be equal to 2 2/5

3 0
3 years ago
Read 2 more answers
What are the possible vaules of x it (4x-5)2=49?
d1i1m1o1n [39]

\boxed{The\:value\:of\:x\:is\:7.375.}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

(4x - 5)2 = 49 \\ ⇢8x - 10 = 49 \\⇢8x = 49 + 10 \\  ⇢8x = 59 \\ ⇢x =  \frac{59}{8}  \\ ⇢x = 7.375

Therefore, the value of x is 7.375.

{ \bf{ \underbrace{To\:verify :}}}

(4x - 5)2 = 49 \\ ⇢(4 \times 7.375 - 5)2 = 49 \\ ⇢(29 .5 - 5)2 = 49 \\ ⇢24.5 \times 2 = 49 \\ ⇢49 = 49 \\ ⇢ L.H.S.=R. H. S

Hence verifed.

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}

8 0
2 years ago
Read 2 more answers
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