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yuradex [85]
3 years ago
14

What is 60/9 as a mixed number in simplest form

Mathematics
2 answers:
Zepler [3.9K]3 years ago
8 0
The greatest multiple of 9 that's less than 60 is 54. 54 divided by 9 is 6. The remainder is 60-54 = 6, which must be put over the 9 as a fraction. This fraction can then be simplified to 2/3. Therefore 60/9 as a mixed number is 6 <span>2/3</span>
Ivanshal [37]3 years ago
5 0
6 tenths over 9. woot
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krok68 [10]

Answer: 46 or 46=4

Step-by-step explanation:

Do what's in the Parenthesis first so 7+2=10 which now give you the equation

[10x 5-4]=2+2

Now we Multiply so we do 10x5 which is 50 so that now gives us the equation[50-4]=2+2

Now we add the 2+2 which is 4 giving us the equation [50-4]=4

Now we subtract 50-4 giving 46

46=4

5 0
3 years ago
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cricket20 [7]

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Add 2y and y.

Step-by-step explanation:

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4 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

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3 years ago
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