Answer:
i would say i love you to them and i want a biggest hug and kiss on a cheek
Explanation:
How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
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This is no Not equivalent
Dilation involves changing the size of a line segment
The scale factor is 2
From the question (see attachment), we have the following side lengths



So, the scale factor (k) from AB to A'B' is calculated using the following scale factor formula

This gives

Divide 2.5 by 1.25

Hence, the scale factor is 2
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The run number is an index to complete factory records on exactly how a specific sheet of laminate was produced. If you have a technical service problem to be solved by the Product Quality Laboratory, provide the run number for the problem material.