Answer:
frequency of allele “A” is .39
frequency of allele “a” is .77
Explanation:
hardy weinberg equation
p^2 + 2pq + q^2 = 1 or (A+a)^2
p^2 = (AA)
2pq = (Aa)
q^2 = (aa)
AA -> 15/100 = .15
Aa -> 25/100 = .25
aa -> 60/100 = .60
if p^2 = AA = .15 then A = √.15 = 0.38729833462 = .39
if q^2 = aa = .60 then a = √.60 = 0.77459666924 = .77
wikipedia quoraAnkitGauba
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Hopefully this helps :)
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Association fibers is the answer
