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noname [10]
3 years ago
7

Please help me with this question! I have 70% in math and the test will give me 30 more points!

Mathematics
2 answers:
jenyasd209 [6]3 years ago
3 0

Answer:

-2.86

-.37

.19

.91

1.46

Step-by-step explanation:

kumpel [21]3 years ago
3 0

Answer: -2.86, -0.37, 0.19, 0.91, 1.46

Step-by-step explanation:

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336 divided by 12 using partial quotients
tensa zangetsu [6.8K]

Answer:

The partial quotients are 20 and 8. The quotient is 28.

Step-by-step explanation:

The dividend is 336 and divisor is 12.

Find the easy factors of 12, which are less than 336.

12\times 10=120

12\times 20=240

12\times 30=360

Since 360>336, therefore 30 cannot be a partial quotient.

So, 20 is a partial quotient. Subtract 240 from 336. Apply this process till the dividend become 0.

The remaining dividend is

336-240=96

Find the easy factors of 12, which are less than 96.

12\times 8=96

The number 8 is a partial quotient.

96-96=0

Now the dividend is zero, so the partial quotients are 20 and 8. The quotient is the sum of partial quotients

20+8=28

The quotient is 28.

8 0
3 years ago
Assume a test for a disease has a probability 0.05 of incorrectly identifying an individual as infected (False Positive), and a
Nana76 [90]

Answer:

0.00002 = 0.002% probability of actually having the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Having the disease

Probability of having a positive test:

0.05 of 1 - 0.000001(false positive)

0.99 of 0.000001 positive. So

P(A) = 0.05*(1 - 0.000001) + 0.99*0.000001 = 0.05000094

Probability of a positive test and having the disease:

0.99 of 0.000001. So

P(A \cap B) = 0.99*0.000001 = 9.9 \times 10^{-7}

What is the probability of actually having the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{9.9 \times 10^{-7}}{0.05000094} = 0.00002

0.00002 = 0.002% probability of actually having the disease

6 0
3 years ago
There are 56 trees in an apple orchard. They are arranged in equal rows. There are 8 trees in each row. How many rows of apple t
zhannawk [14.2K]

Answer:

7

Step-by-step explanation:

7 0
3 years ago
Matt bought a new car at a cost of $25,000. The car depreciates approximately 15% of its value each year. What will the car be w
White raven [17]
The car will be worth $4,921.86
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3 years ago
What’s the slope intercept equation of the line that goes through the points (1,5) and (2,8)
mafiozo [28]

Answer:y=3x+2

Step-by-step explanation:

6 0
3 years ago
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