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3 years ago

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Mathematics

1 answer:

irinina [24]3 years ago

6 0

X4 hm I’m pretty sure that’s it

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An advertising agency that serves a major radio station wants to estimate the mean amount of time the station’s audience members

Flura [38]

Answer:

$n=(\frac{1.645(45)}{5})^2 =219.18 \approx 220$

So the answer for this case would be n=220 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\sigma = 45$ represent the population deviation

$ME = 5$ represent the margin of error

The margin of error for the true mean is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (4) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 90% of confidence interval now can be founded using the normal distribution. The significance level is $\alpha=1-0.9=0.1$ and the critical value would be $z_{\alpha/2}=1.645$ , replacing into formula (b) we got:

$n=(\frac{1.645(45)}{5})^2 =219.18 \approx 220$

So the answer for this case would be n=220 rounded up to the nearest integer

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defon

The way you put it is confusing. I'll answer but the way you put it was confusing to me.

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