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iris [78.8K]
2 years ago
15

Find the solution of the system of equations. -x+2y=-15 8x-2y=-20

Mathematics
1 answer:
Grace [21]2 years ago
8 0

Answer:

the answer is (-5,-10)

hope this helps :)

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You have a credit card balance of %188, and you pay annual interest on the unpaid balance of 18%. If you pay $50 on your balance
GaryK [48]
$27.79. First multiply the percentage as a decimal out of 100. Subtract that number from the original amount. Do the same thing with the number you got from subtracting(multiply by percentage then subtract from starting amount(the new one)) you end up with $27.79

5 0
3 years ago
Which represents where f(x) = g(x)?
ANEK [815]

Answer:

f(2) = g(2) and f(0) = g(0)

Step-by-step explanation:

When x = x in f(x) and g(x), that means the two functions are equal.

7 0
3 years ago
A grasshopper covered a distance of 5 yards in 9 equal hops. How many yards did the grasshopper travel on each hop?
andre [41]

Answer:

a)5/9 yards=0.556yards

b)10/9 yards=1.11 yards

Step-by-step explanation:

for the part a

To solve this exercise we must divide the total distance traveled by the grasshopper (5 yards) by the number of jumps that were made (9).

d=\frac{5}{9}

if you use the calculator you will realize that the value is 0.55yards

for the part b

knowing the distance traveled in a jump, we multiply this value by two to find out how much is the distance traveled in 2 jumps

d=\frac{2x5}{9} =\frac{10}{9}

if you use the calculator you will realize that the value is 1.11 yards

4 0
3 years ago
Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = 3 over 2 x +5.
Oliga [24]
We have that

<span>Write an equation of a line that passes through the point (2, 3) and is parallel to the line y = (3/2)x +5

parallel lines are the same slope
then
m=(3/2)

step 1

find the equation of a line with
m=3/2  and point (2,3)

y-y1=m*(x-x1)----------> y-3=(3/2)*(x-2)------> y=(3/2)x

the answer is
y=(3/2)x
</span><span>y = 3 over 2 x

see the attached figure</span>

8 0
2 years ago
Ac method for x^2+20x-8=0
yanalaym [24]
<h2>Explanation:</h2><h2></h2>

By using quadratic formula:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\quad a=1,\:b=20,\:c=-8

x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}

x=\frac{-20+\sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}:\quad 2\left(3\sqrt{3}-5\right)

x=\frac{-20-\sqrt{20^2-4\cdot \:1\left(-8\right)}}{2\cdot \:1}:\quad -2\left(5+3\sqrt{3}\right)

So the solutions are:

\boxed{x=2\left(3\sqrt{3}-5\right),\:x=-2\left(5+3\sqrt{3}\right)}

5 0
3 years ago
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