Question

Akira is folding a piece of paper that is 0.2 millimeters thick in half. The thickness of the paper doubles with each fold. Let n represent the fold number and t(n) represent the thickness of the paper. Which exponential function represents this scenario?

Answer 1

Answer:

t(n)= 0.2 * 2ⁿ

Step-by-step explanation:

Thickness= 0.2 millimeters

paper = 1

n= number of folds

The exponential function will be given by

t(n)= 0.2 * 2ⁿ

so if there's a single fold

t(1)= 0.2 * 2¹

t(1)= 0.4 mm

Now for 2 folds the thickness will be

t(2) = 0.2 *2 ²

t(2)= 0.2 *4

t(2) = 0.8mm

The exponential that represents this scenario is

t(n)= 0.2 * 2ⁿ

And for 3 folds the thickness will be

t(3) = 0.2 *2 ³

t(3)= 0.2 *8

t(3) = 1.6 mm