The answer is 80°.
If there is a line segment in a triangle which cuts two sides in half or if there is a line segment between two midpoints of a triangle's sides, that line segment must be parallel to the remaining side.
In this case, point L is the midpoint of FH, and point K is the midpoint of HG. So, LK is parallel to FG.
When a line cuts two parallel lines, there are angle pairs which are equal. In the problem above, the line segment FH cuts KL and GF.
The angles KLH and GFH are what we called "Corresponding Angles" and they are equal.
So if HFG is 80°, HLK must be equal to 80°
Let's move like a crab, backwards some.
after 2 years?

after 3 years?

is that enough to pay the $1100?
now, let's write 1000(1+r)² in standard form
1000( 1² + 2r + r²)
1000(1 + 2r + r²)
1000 + 2000r + 1000r²
1000r² + 2000r + 1000 <---- standard form.
The distance between any 2 points P(a,b) and
Q(c,d) in the coordinate plane, is given by the formula:<span>
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Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.





Answer: B and D
Answer:
Step-by-step explanation:
suppose that O has coordinates (0,0),and the points P and Q have coordinates that are whole numbers between 0 and 2, inclusive. One example of a triangle with O,P, and Q as vertices is shown below . how many such triangle are right triangle ?
Answer:
actually it is
Step-by-step explanation:
i skipped the whole question except the last sentence's few words