Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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Answer: v= pie r^2 h/3
Step-by-step explanation:
4 squared+ 12 squared= c squared
16+144=160
Square root 160
so your answer would be 12.6
Answer:
4) choice a 30%
5) choice b 62.5%
Step-by-step explanation:
4) 3/10 = 0.30 or 30%
5) 5/8 = 0.625 or 62.5%
