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3 years ago

10

Consider the two functions below which one of these functions in the line year what is its equation answer any answer totwo deci

mal places

1 answer:

zvonat [6]3 years ago

8 0

Answer:

The thing u pasted is glitched and isn't loading

Step-by-step explanation:

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How many times does 1/4 go into 3/8?

Luba_88 [7]

3/8 divided by 1/4

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Rapid Rental Car charges a $30 rental fee, $15 for gas, and $0.65 per mile driven. For the same car, Capital Cars charges $35 fo

andreev551 [17]

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3 years ago

If there is a 10% chance of sun tomorrow and a 20% chance of wind and no sun, what is the probability that it is windy, given th

professor190 [17]

Since there are two events happening simultaneously (windy and no sun), we can apply the concept of conditional probability here. P(A|B) = P(A∩B)/P(B) where it means that given B is happening, the probability that A is happening as well is the ratio of the chance for A and B to happen simultaneously over the chance of B to happen. For our case, this can be interpreted as P(A|B): it is the probability that it is windy (A) GIVEN that there is no sun (B) P(A∩B) : chance of wind and no sun P(B) : chance that there is no sun tomorrow The chance of P(A∩B) is already given as 20% or 0.20. Since there is 10% or 0.10 chance of sun, then chances of having no sun tomorrow is (1-0.10) = 0.90. Thus, we have P(A|B) = 0.2/0.9 ≈ 0.22 or 22%. So, answer is B: 22%<span>.</span>

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A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

3 years ago