Answer:
The smaller bottle holds 12.5 ml of perfume.
====================
<h2>Given</h2>
- Two bottles of similar shape;
- Larger bottle has volume of 100 ml;
- The length of larger bottle is 10 cm;
- The length of smaller bottle is 5 cm.
<h2>To find </h2>
- The volume of smaller bottle.
<h2>Solution</h2>
Find the scale factor, the ratio of corresponding dimensions:
We know the volume is the function of three dimensions, therefore the ratio of volumes is the cube of the scale factor:
Substitute the known values and find the volume of small bottle:
The smaller bottle holds 12.5 ml of perfume.
This problem is basically asking:
Which would mean 
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.
We will use volume of cylinder formula to solve our given problem as:
, where,
r = Radius,
h = Height of cylinder.
Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be 
meters at 
.
Upon substituting these values in above formula, we will get:
Now, we will take positive square root of both sides as radius cannot be negative.
Therefore, radius of tank would be approximately square root of 10 m.
<em>Answer:</em>
<em>Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there is 1 number to the right of the decimal point, place the decimal number over </em>
<em>10 1
</em>
<em> (10
). Next, add the whole number to the left of the decimal.
</em>
<em>1 2
/10
</em>
<em>Reduce the fractional part of the mixed number.
</em>
<em>1 1
/5
</em>
<em>Reduce the fraction.
</em>
<em>6/
5
</em>
<em />
<em>Step-by-step explanation:</em>
<em />
