Question

Can someone help me on problem one and if you can and only if you want can you also help me on two btw please show work I will give branily crown thing.

Answer 1

PROBLEM #1:

As the problem is, we are adding a negative. I can change this to be a subtraction problem. It looks like this: $2\frac{1}{3} - 1\frac{1}{5}$.

To be able to add or subtract fractions/mixed numbers, we have to first get common denominators. A common denominator is a shared multiple between two numbers. So, we need to find the smallest number that both 3 and 5 (the denominators of each fraction) can do into evenly. In this case, that number is 15! To transform the fractions to have common denominators, we will multiply 1/3 by 5/5 and 1/5 by 3/3 (multiply the top and bottom by 5 or 3 so that the denominator is 15). Here is our new problem: $2\frac{5}{15} - 1\frac{3}{15}$.

All that's left to do now is subtract! Since our first fraction is larger (this is important!) we don't need to do any borrowing. So, we'll subtract 2 - 1 = 1, and 5/15 - 3/15 = 2/15. Therefore, if we put those pieces back together, we get 1 2/15 ($1\frac{2}{15}$).

PROBLEM #2:

For this problem, we have two negative mixed numbers. In this case, we will simply be adding the negative numbers because both are negative. For example, -2 + -4 = -6. Here is the rewritten problem: $-3\frac{1}{2} + -5\frac{1}{3}$.

Our first step is to get common denominators. In this case, that common denominator will be 6: $-3\frac{3}{6} + -5\frac{2}{6}$.

Now, we have to add! -3 + -5 = -8, -3/6 + -2/6 = -5/6. Once we've added the parts, we can put them back together to form the answer: -8 5/6 ($-8\frac{5}{6}$).

Hope this helps!! :)

Answer 2

Answer:

17/15 _53/6

Step-by-step explanation:

The other is problem 1 and the other is problem 2