What is the result?? Show explanation.A. 4⁵B. 4¹C. 4-¹D. 4-⁵
2 answers:
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I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have
Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system
If we solve the first two equations for y squared, we have
And we can deduce
So that the third equation becomes
(we can't accept the negative root because negative lengths make no sense)
(a) The vertices after the reflection in the line x = 5 are F'(4,6) , G'(2,8) , H'(2,3) .
and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .
In the question a triangle FGH with vertices F(6,6) , G(8,8) and H(8,3) is given
Part (a)
the rule for reflection of point (x,y) by the line x = p is
(x,y) → (2×p - x , y)
reflection by the line x = 5 ,
we get
the vertices as
(2×5-6,6) = (4,6)
G'(2×5-8,8) = (2,8)
H'(2×5 - 8 ,3) = (2,3)
Part (b)
the rule of translation is given as (x,y)→ (x - 7, y - 9)
So , the vertices after translation are
F''(6-7 , 6-9) = (-1,-3)
G''(8-7,8-9) = (1,-1)
H''(8-7,3-9) = (1,-6)
Therefore , (a) The vertices after the reflection in the line x = 5 are F'(4,6)
G'(2,8) , H'(2,3) .
and (b) after translation , the vertices are F''(-1,-3) , G'' (1,-1) , H''(1,-6) .
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