Answers:
13 42 m; B; 0.57 m
Step-by-step explanation:
Data:
Pool A: r = 22 ft
Pool B: D = 13.6 m
Calculations:
1. Radius of Pool A
r = 22 ft × (0.305 m/1 ft) = 6.71 m
2. Diameter of Pool A
D =2r = 2 × 6.71 = 13.42 m
The diameter of Pool A is 13.42 m.
3. Compare pool diameters
The diameter of Pool B is 13.6 m.
So, the diameter of Pool <u>B</u> is greater.
4. Compare circumferences
The formula for the circumference of a circle is
C = 2πr or C = πD
Pool A: C = 2π × 6.71 = 42.16 m
Pool B: r = π × 13.6 = 42.73 m
Pool B - Pool A = 42.73 - 42.16 = <u>0.57 m
</u>
The circumference is greater by <u>0.57 m.</u>
Answer:
C) -2 ≤ x ≤ 2
Step-by-step explanation:
Domain is the set of x-values that can be inputted into function f(x).
We see that our x-values span from -2 to 2. Since they are both closed dots, we include them in the domain:
[-2, 2] or -2 ≤ x ≤ 2
Answer:
11.27
Step-by-step explanation:
Answer:
![\huge\boxed{\sqrt[3]{c^4}=c^\frac{4}{3}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\text{therefore}\\\\\sqrt[3]{c^4}=c^\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Ctext%7Btherefore%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D)
