Answer:Area of part 1:
A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2
Area of part 2:
A2=length*width=(8+2)*1=10 ft2
Area of part 3:
A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2
Total area of the reactangle : A=16*8=128 ft2
Total area of the nonshaded region : 128-41=87 ft2
Step-by-step explanation: Plz make brainliest
Answer:
g(x) = –3(x + 6)2 + 48.
Step-by-step explanation:
The graph of f(x) = x2 is shifted right 6 units. The graph of f(x) = x2 is shifted down 48 units. The graph of f(x) = x2 is reflected over the y-axis.
1. You have that:
- Each gallon of paint covers 400 ft²<span>.
- One side of a wall must be painted and its dimensions are :is 8 meters tall and 40 meters long.
1 ft=0.3048 m
1 ft</span>²=(0.3048 m)²=0.09290 m²
2. Each gallon of paint covers 400 ft<span>², then:
</span>
400 ft²x<span>0.09290=37.16 m</span>²
3. The area of one side of the wall is:
A=8 mx40 m
A=320 m²
4. Therefore, you have:
1 gallon-----37.16 m²
x-----320 m²
x=320x1/37.16
x=8.61 gallons
x≈9 gallons
The answer is: 9 gallons
To find the surface area, you just find the area of every side and then add them up.
