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3 years ago

15 Points! Giving Brainliest

Mathematics

1 answer:

NARA [144]3 years ago

8 0

Answer: A≈153.94

3.14 x 7 = 153.94

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Triangle ABC is transformed to triangle A'B'C', as shown below:

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Answer:

Step-by-step explanation:

d). = m∠BCA = m∠B'C'A'

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Clay has 5 pounds of beef. How many 8 ounce servings does he have? *

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Step-by-step explanation:

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In the equation -y = 10x, what is the unit rate?

Umnica [9.8K]

You have to multiply by a -1 both sides,
it would be 10 1/2

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3 years ago

After 3/4 of a minute a sloth has moved just 3/8 of a foot. what is the sloth's speed in feet per minute

Delicious77 [7]

Hello!

So 4/4 - 3/4 = 1/4 (a quarter). So we have to find a quarter of 3/8 and add it to 3/8. First of all, we have to convert 1/4 to a percentage. The answer is 25%. 3/8 as a decimal is 0.375. 25% of 0.375 = (0.25 x 0.375 =) 0.09375.
0.09375 + 0.375 = 0.46875.
Now, we have to convert 0.46875 back into a fraction.

So the answer is 5/64.

Have a great day! :)

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3 years ago

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found: