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2 years ago

15 Points! Giving Brainliest

Mathematics

1 answer:

NARA [144]2 years ago

8 0

Answer: A≈153.94

3.14 x 7 = 153.94

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A coin is biased to show 39% heads and 61% tails. The coin is tossed twice. What is the probability that the coin turns up tails

julia-pushkina [17]

I'm pretty sure that this is a trick question, the answer is 61%.

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3 years ago

Please help meeeeeeeeeee

Darina [25.2K]

If you need help for all 3 questions then ok.
Here’s what you need to do. If they give you a rectangular prism with a side length of #, that number is the length, width and height. I’ll help you for the first picture. They asked how many cubic blocks with a SIDE LENGTH of 1/7 in can fill in a cube with the SIDE LENGTH of 3/7 in. Here is your equation: (3/7 x 3/7 x 3/7) / (1/7 x 1/7 x 1/7). That’s how you solve it. (The slash stands for division.) Now do the same thing with the other pictures. They will ask you how many blocks with a side length of # can fill in a prism with the length, width, and height (or just a side length without saying the l, w and h.) Hopefully this helped! If I got it wrong or if you need help cause you didn’t get what I mean, let me know.

bYe

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2 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

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3 years ago

Which statement is true about this function h(x) = 2^x-5

Marysya12 [62]

Answer:

$\frac{1}{32} x$

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Austin is 69 years younger than Jamie. 3 years ago, Jamie's age was 4 times Austin's age. How old is Austin now?

matrenka [14]

Answer: 26 years old

Step-by-step explanation:

Create an equation with Austin as x and Jamie as x+69 (I just like workin with addition signs more)= 4(x-3)= x+69-3
Simplify the equations --> 4x-12=x+66
Solve the equation: 3x-12=66 --> 3x=78 --> x=26

This is the same as other age problems, just with the extra step of distributing the multiplication.

4 0

2 years ago