All categories

2 years ago

Which equation represents a line with an undefined slope? y = x y = –x y = 0 x = 0

Mathematics

2 answers:

malfutka [58]2 years ago

7 0

Answer:

x=0

Step-by-step explanation: If x=0, then two points on the graph can be (0, 6) and (0,0). using those two points, you can say the slope is 6/0, which is undefined

zzz [600]2 years ago

4 0

Answer: x=0 i believe correct me if im wrong

You might be interested in

The equations below represent the numbers y of tickets sold after x weeks for two different local music festivals.

kiruha [24]

Answer:

Part a) 3.5 weeks

Part b) 185 tickets

Step-by-step explanation:

Part a) After how much time have the same number of tickets been sold for both festivals?

Let

x -----> the number of weeks

y ----> the number of tickets sold

we have

<em>Country Music Festival</em>

$y=10x+150$ ----> equation A

<em>Pop Music Festival</em>

$y=20x+115$ ----> equation B

Equate equation A and equation B

$20x+115=10x+150$

solve for x

$20x-10x=150-115$

$10x=35$

$x=3.5\ weeks$

Part b) What is the number of tickets sold at that time?

substitute the value of x=3.5 weeks in the linear equation A or linear equation B

$y=10(3.5)+150$

$y=35+150$

$y=185\ tickets$

6 0

2 years ago

Two positive improper are multiplied. Is the product sometimes, always, or never less than 1? EXPLAIN.

TEA [102]

The answer is sometimes less than 1

7 0

3 years ago

Help please, just number 3, thats all im asking, thanks.

Bezzdna [24]

The rectangle that has area 400 has width 10, so its length is 40.

A = LW; L = A/W = 400/10 = 40

The length is 10 + 0.2 = 10.2. The width is 10 + 2 = 12

The multiplication is 10.2 * 12

40.2 * 12 = 40 * 10 + 0.2 * 10 + 40 * 2 + 0.2 * 2

40.2 * 12 = 400 + 2 + 80 + 0.4

40.2 * 12 = 482.4

4 0

2 years ago

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

3 0

2 years ago

Solve and type in 'ab' 8×a=32,a+26=b+1,a<20<b

Whitepunk [10]

8*a=32
32:8=a
4=a

4+26=b

30=b

3 0

3 years ago