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2 years ago

Given f(x)=3x-1 and g(x)=2x-3, for which value of X does g(x)=f(2)?

Mathematics

2 answers:

son4ous [18]2 years ago

4 0

X must be 4.
I uploaded the photo as an answer

lana [24]2 years ago

4 0

Answer:

For the value of 4.

Step-by-step explanation:

Given,

f(x)=3x-1 -----(1),

g(x)=2x-3 ------(2),

From equation (1),

f(2) = 3(2) - 1 = 6 - 1 = 5, ----(3)

If, g(x)=f(2)

From equation (2) and (3),

2x - 3 = 5

2x = 8 ( Additive property of equality )

x = 4 ( Division property of equality )

Hence, for the value of x equal to 4, g(x) = f(2) is true.

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Read 2 more answers

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0

2 years ago