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3 years ago

Given f(x)=3x-1 and g(x)=2x-3, for which value of X does g(x)=f(2)?

Mathematics

2 answers:

son4ous [18]3 years ago

4 0

X must be 4.
I uploaded the photo as an answer

lana [24]3 years ago

4 0

Answer:

For the value of 4.

Step-by-step explanation:

Given,

f(x)=3x-1 -----(1),

g(x)=2x-3 ------(2),

From equation (1),

f(2) = 3(2) - 1 = 6 - 1 = 5, ----(3)

If, g(x)=f(2)

From equation (2) and (3),

2x - 3 = 5

2x = 8 ( Additive property of equality )

x = 4 ( Division property of equality )

Hence, for the value of x equal to 4, g(x) = f(2) is true.

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Answer:

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2 years ago

Let A be the set of all lines in the plane. Define a relation R on A as follows. For every l1 and l2 in A, l1 R l2 ⇔ l1 is paral

Lyrx [107]

Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

Given :

A be the set of all lines in the plane and R is a relation on set A.

$R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}$

To find :

Which type of relation R on set A.

Explanation :

A relation R on a set A is called reflexive relation if every $a\in A$ then $(a,a)\in R$ .

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if $(a,b)\in R$ then $(b,a)\in R$ for all $a,b\in A$ .

So, the relation R is a symmetric relation because if a line $l_1$ is parallel to the line $l_2$ the always the line $l_2$ is parallel to the line $l_1$ .

A relation R on a set A is called transitive relation if $(a,b)\in R$ and $(b,c)\in R$ then $(a,c)\in R$ for all $a,b,c\in A$ .

So, the relation R is a transitive relation because if a line $l_1$ s parallel to the line $l_2$ and the line $l_2$ is parallel to the line $l_3$ then the always line $l_1$ is parallel to the line $l_3$ .