A plane at 3,800 feet is descending at a rate of 120 feet per minute, and a plane at 520 feet is climbing at a rate of 40 feet p
er minute. In how many minutes will they be at the same altitude? Write a system of equations. Then graph the system to determine the solution.
1 answer:
so the basic formula for this d = rt
where d is the distance , r is the speed and t
is time
3800 – 120t = 520 + 40t ( this is the altitude
of each plane are equal)
Solve for t
T = 20.5 min time it takes for the planes to be
at the same altitude
3800 – 120(20.5) = 1340 ft
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