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2 years ago

Someone hurry and help plsss

Mathematics

1 answer:

Damm [24]2 years ago

5 0

Answer:

-3 is the answer for the question

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FIRST PERSON GETS BRAINLIEST

Sunny_sXe [5.5K]

X = 61 degrees.
Find the number of degrees in a pentagon by using the following formula:
(number of sides - 2)180 = 540.
There are 540 degrees in a pentagon.
Since we know four of the angles, we can subtract them from 540 to get the fifth angle.
540-138-144-107-90 = 61

Hope this helped =)

3 0

3 years ago

Read 2 more answers

Ed has 28 blocks. Sue has 34 blocks who has more blocks? How many more?

Anna007 [38]

Answer:

Sue // 6 More blocks

Step-by-step explanation:

Sue has more blocks because 34>28.

34-28 is 6 so sue has 6 more.

3 0

2 years ago

Read 2 more answers

Evaluate 1.80/Y for y= 0.009 express your answer is in simplest form.

igomit [66]

Evaluate 1.80/Y for y= 0.009

We replace 0.009 for y

So fraction becomes $\frac{1.80}{0.009}$

Now , to simplify the fraction we try to remove the decimal from denominator

0.009 have three digits after the decimal point, so we multiply by 1000 to remove the decimal point. Multiply top and bottom by 1000 to make equivalent fraction.

$\frac{1.80*1000}{0.009*1000}$

$\frac{1800}{9}$ = 200

Answer is 200

3 0

3 years ago

find the value of x of given figure and solve this question step by step plzz help question number D

Alinara [238K]

Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

So in BDC

$Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm$

Applying Pythagoras theorem:

$(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm$

Solving for triangle ABC

$Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\$

Applying Pythagoras theorem

$AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm$

Hence,

x=15 cm

8 0

2 years ago

Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.f(x)=(3x-4)(-6x+5)

Umnica [9.8K]

At first glance, it might be tempting to say this is a linear function, because we see linear terms (3x and –6x); however, these are multiplied together, so it's actually a quadratic.

We need to expand the function (hint: use FOIL) to identify the terms.

$f(x)=(3x-4)(-6x+5)=-18x^2+39x-20$

The x^2-term, or quadratic term, is $-18x^2$ . The x-term, or linear term, is $39x$ . The number term, or constant term, is –20.

4 0

3 years ago