<h3>= 35% × $70 ÷ 100</h3><h3>= 24.5</h3><h3>= $70 - 24.5</h3><h3>= 45.5</h3><h3>= 5% × 45.5 ÷ 100</h3><h3>= 2.275</h3><h3>= 2.275 + 45.5</h3><h3>= ~$47.775</h3><h3>= <u>$</u><u>48</u></h3><h3>Janet Will Have Enough Money Left Over For A Movie Ticket.</h3>

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4 0

2 years ago

Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form

ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

$\frac{n!}{n1!*n2!*...*nk!}$

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

$\frac{10!}{2!*2!*2!*2!*2!}=113,400$

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

$\frac{10!}{2!*2!*3!*3!}=25,200$

So, If each team has either two or three students, The number of ways form teams are:

113,400 + 25,200 = 138,600

6 0

3 years ago