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MissTica
2 years ago
5

Four men take 6 days to complete a certain work. Find the number of men needed to complete the same work in 8 days

Mathematics
2 answers:
Andru [333]2 years ago
4 0

Answer:

the answer is 5 men i think

spin [16.1K]2 years ago
4 0
The guy above me is right
You might be interested in
Given that Triangle ABC such that<br>a=8cm, b=7cm and c=9cm<br>tem and c= 9cm find Cos B​
charle [14.2K]

Answer:

We use cosine rule also called cosine law which states

c^2=a^2+b^2-2abcosC

given

a=8cm, b=7cm, c=9cm cos C?

9^2=8^+7^2-2*8*7 cos C

expand

81=64+49-112 cos C

like terms together

81-113=-112 cos C

-32=-112cos C

multiply both sides by -1

32=112cos C

divide both sides by 112

32/112=cos C

cosC=0.2857

find cos inverse of 0.2857

angle C= 73.40

4 0
3 years ago
Point M is located in the third quadrant of the coordinate plane, as shown.
Angelina_Jolie [31]
(-5.5,2) is the answer
4 0
3 years ago
Read 2 more answers
It’s not 0.615 , or 0.75 or the one shown in the picture
Dafna1 [17]
2.40714

1) Let's evaluate that expression, given that a=4.9, b=-7, and c=-0.5

\begin{gathered} a^3\div b^2+c^3 \\ (4.9)^3\div(-7)^2+(-0.5)^3= \\ \frac{4.9^3}{\left(-7\right)^2+\left(-0.5\right)^3} \\  \\ \frac{4.9^3}{48.875} \\  \\ \frac{117.649}{48.875} \\  \\ 2.40714 \end{gathered}

Note that we have rewritten it as a fraction so that we can easily operate. Also, we have applied here the PEMDAS order of operations, prioritizing the exponents.

6 0
1 year ago
What is the greatest common factor of 42, 56, and 112
VashaNatasha [74]

Answer: gcf, hcf, gcd (42; 112) = 14 = 2 × 7: greatest (highest) common factor (divisor), calculated.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A random sample of 100 observations from a quantitative population produced a sample mean of 22.8 and a sample standard deviatio
natima [27]

Answer:

We conclude that the population mean is 24.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 24

Sample mean, \bar{x} = 22.8

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 8.3

First, we design the null and the alternate hypothesis

H_{0}: \mu = 24\\H_A: \mu \neq 24

We use Two-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{22.8 - 24}{\frac{8.3}{\sqrt{100}} } = -1.44

We calculate the p-value with the help of standard z table.

P-value = 0.1498

Since the p-value is greater than the significance level, we accept the null hypothesis. The population mean is 24.

Now, z_{critical} \text{ at 0.05 level of significance } = \pm 1.96

Since,  the z-statistic lies in the acceptance region which is from -1.96 to +1.96, we accept the null hypothesis and conclude that the population mean is 24.

7 0
3 years ago
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