![Vertex: \ (2,3)](https://tex.z-dn.net/?f=Vertex%3A%20%5C%20%282%2C3%29)
<h2>
Explanation:</h2>
The vertex form of the equation of a parabola is given by the following form:
![f(x)=a(x-h)^2+k \\ \\ Where: \\ \\ a:Leading \ Coefficient \\ \\ (h,k):Vertex \ of \ the \ parabola](https://tex.z-dn.net/?f=f%28x%29%3Da%28x-h%29%5E2%2Bk%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20a%3ALeading%20%5C%20Coefficient%20%5C%5C%20%5C%5C%20%28h%2Ck%29%3AVertex%20%5C%20of%20%5C%20the%20%5C%20parabola)
In this exercise, we have the following equation:
![y=-(x-2)^2+3](https://tex.z-dn.net/?f=y%3D-%28x-2%29%5E2%2B3)
From here, we can conclude that:
![Leading \ coefficient: \ -1 \\ \\ Vertex: \ (2,3)](https://tex.z-dn.net/?f=Leading%20%5C%20coefficient%3A%20%5C%20-1%20%5C%5C%20%5C%5C%20Vertex%3A%20%5C%20%282%2C3%29)
Since the leading coefficient is less than zero, the parabola open downward. So, the graph is shown below and the vertex has been indicated.
<h2>Learn more:</h2>
Finding leading coefficient: brainly.com/question/1469367
#LearnWithBrainly
1 is the answer to nthis/...
35×69=35*69
35*69=2415
hopes this helps
For this case we have the following polynomial:
![-3f ^ 3 + 9f + 6f ^ 4 - 2f ^ 2](https://tex.z-dn.net/?f=%20-3f%20%5E%203%20%2B%209f%20%2B%206f%20%5E%204%20-%202f%20%5E%202%20%20)
To answer the question, what we must do is rewrite the polynomial in its standard form.
We have then that the polynomial will be given by:
![6f ^ 4 - 3f ^ 3 - 2f ^ 2 + 9f](https://tex.z-dn.net/?f=%206f%20%5E%204%20-%203f%20%5E%203%20-%202f%20%5E%202%20%2B%209f%20%20)
Therefore, we have the ordered polynomial in descending form of exponents.
Therefore, the second term of the polynomial is:
![- 3f ^ 3](https://tex.z-dn.net/?f=%20%20%20-%203f%20%5E%203%20%20)
Answer:
The second term of the polynomial is given by:
![- 3f ^ 3](https://tex.z-dn.net/?f=%20%20%20-%203f%20%5E%203%20)