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3 years ago

Will give brainliest Of the following sets, which numbers in {1, 2, 3, 4, 5} make the inequality 5x + 2 > 12 true? (5 points)

Mathematics

2 answers:

daser333 [38]3 years ago

6 0

Answer:

x = 3, 4, 5

Step-by-step explanation:

Radda [10]3 years ago

4 0

Answer:

x = 3, 4, 5

Step-by-step explanation:

Solving the inequality

5x + 2 > 12 ( subtract 2 from both sides )

5x > 10 ( divide both sides by 5 )

x > 2

Thus the only values from the given set which make the inequality true are

x = 3, 4, 5

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Side lengths: RS=7 and ST=7, and angle=90 degrees

Why?

Since second coordinates of R and S are the same so we can just count the length by adding first coordinate of R and first coordinate of S= |-3|+4=7

Since first coordinates of R is the same as first coordinate of T so we can just count the length by adding second coordinates of S and T=5+|-2|=7

Angle: RST is =90 degrees because triangle RST is right angled triangle. Why? Because RS is parallel to X axis(the same second coordinates of R and S) and ST is parallel to Y axis(the same coordinates of S and T) .

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2 years ago

Kim has 8 dollars less than twice Ricky. If

olya-2409 [2.1K]

Based on the information given, it should be noted that the correct option is C. 3x - 8.

<h3>Solving equations.</h3>

From the information given, it was stated that Kim has 8 dollars less than twice Ricky. This will be:

= (2 × x) - 8.

= 2x - 8

Also, Ricky has x dollars. Therefore, the amount that they have together will be:

= 2x - 8 + x

= 3x - 8

Learn more about equations on:

brainly.com/question/13763238

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2 years ago

Nola Giles down a trail at a steady rate for 10 minutes. Her change in elevation was -200 feet. Then she continued to hike down

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3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$