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3 years ago

Choose the correct equation

Mathematics

1 answer:

Nataly [62]3 years ago

7 0

Answer:

y = -3x - 10

Step-by-step explanation:

Equation to represent the given table can be written in the slope-intercept form, y = mx + b.

m = slope = ∆y/∆x

Using the coordinates of any two pairs of values from the table, (0, -10) and (1, -13):

Slope (m) = [(-13 - (-10)]/[1 - 0] = -3/1

Slope (m) = -3

b = y-intercept = the value of y when x is 0 = -10

To write the equation, substitute m = -3 and b = -10 into y = mx + b.

Thus:

y = -3x + (-10)

y = -3x - 10

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Find the 13th term of the arithmetic sequence -3x+7, -5x+3, -7x-1, ...

oksano4ka [1.4K]

Answer:

a₁₃ = - 27x - 41

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3x + 7

d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)

= - 5x + 3 + 3x - 7

= - 2x - 4

Then

a₁₃ = - 3x + 7 + 12(- 2x - 4)

= - 3x + 7 - 24x - 48

= - 27x - 41

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3 years ago

Is 1/8 - 10(3/4-3/8x)+5/8x equivalent to -1/8(59-35x)

madreJ [45]

Answer:

Yes

Step-by-step explanation:

1/8-10(3/4-3/8x)+5/8x

1/8-(30/4-30/8x)+5/8x

1/8-30/4+30/8x+5/8x

Lcm is 8

1-60+30x+5x/8

-59+35x/8

Factorise

-1/8(59-35x)

So when comparing the two,they are observed to be the same

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3 years ago

Ten out of every 32 people

rosijanka [135]

10 divided by 32 is 32.25
multiply 32.25 by 100
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3 years ago

Determine the domain and range of (g ○ f)(x) if f of x is equal to 9 over the quantity x squared minus 9 end quantity and g(x) =

Bezzdna [24]

The domain is all real numbers except -6 and 0. Hence, domain D: {x ∈ ℝ| x ≠ –6, 0}

Hence the range is all real numbers except -3 and 3. Hence, range R: (–∞, –3) ∪ (3, ∞)

Given the following functions:

$f(x)=\frac{9}{x^2-9}\\g(x)=x+3$

First we need to get the composite function f(g(x))

$f(g(x)) = f(x+3)\\f(x+3)=\frac{9}{(x+3)^2-9} \\f(x+3)=\frac{9}{x^2+6x+9-9} \\f(x+3)=\frac{9}{x^2+6x} \\$

Get the domain

The domain the values of x for which the function exists. The function cannot exists at when x = -6 and x = 0

Hence the domain is all real numbers except -6 and 0. Hence, domain D: {x ∈ ℝ| x ≠ –6, 0}

The range is the value of y for which the function exists. The function cannot exists at when x = -6 and x = 0

Hence the range is all real numbers except -3 and 3. Hence, range R: (–∞, –3) ∪ (3, ∞)

Learn more here: brainly.com/question/20838649

6 0

3 years ago

Read 2 more answers

How do you complete the square to rewrite y= x^ -6x + 15 in vertex form

Vaselesa [24]

Vertex form of a quadratic equation is $y=a(x-h)^{2}+k$
where (h, k) is the vertex.

Our aim is to write the expression $y=x^{2} -6x+15$ in the form
$y=a(x-h)^{2}+k$

$y=x^{2} -6x+15$

$y=x^{2} -2*3*x+15$

$y=(x^{2} -2*3*x+ 3^{2})-3^{2}+ 15$

$y=(x-3)^{2}-9+15$

$y=(x-3)^{2}+6$

5 0

3 years ago