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ycow [4]
2 years ago
12

PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!

!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!
PLSSSSS SHOWWW THE WORKKKK!!!!!!!

Mathematics
1 answer:
pogonyaev2 years ago
5 0
2x^3y^4. That how you do this
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I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
2 years ago
Find the asymptotes of the function. Select all that apply.
devlian [24]

An asymptote is a vertical horizontal or oblique line to which the graph of a function progressively approaches without ever touching it.

To answer this question we observe the graph. All the values of x and y must be identified for which the graph of the function tends to infinity.

It is observed that these values are:

x = -1

x = 3

y = 0

The first two corresponds to the equations of a vertical line. The third corresponds to horizontal line, the axis of x. It can be seen that although the graph of the function is very close to these values, it never "touches" them

5 0
3 years ago
Read 2 more answers
Tell what number must be added to complete the square<br> x^2+16x__
Talja [164]
2 will work.
if you use two the answer is.
(x-4)(x+4)
8 0
3 years ago
1. Ramon spends 2/5 of his monthly income on rent, 1/5 of his monthly income on utilities, and 3/4 of the amount remaining on fo
hichkok12 [17]
If x is how much his income is then 2/5x+1/5x= 3/5x for rent and utilities. x-3/5x=2/5x leftover. 3/4×2/5x=3/10x for food. 3/5x+3/10x=9/10x spent on rent, utilities, and food and rec. He saves the rest which is x-9/10x= 1/10x so if 1/10x=193.50
x= $1,935 for his income
7 0
2 years ago
A bag contains 10 black jellybeans, 12 green ones, 3 orange ones, and 20 blue ones. if you reach in and grab one randomly, what
Degger [83]
10/45 for black
12/45 for green
3/45 for orange (can be simplified to: 1/15)
20/45 for blue
6 0
3 years ago
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