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Elodia [21]
3 years ago
14

In standard form 0.0325 is written as?

Mathematics
2 answers:
Mice21 [21]3 years ago
8 0

Answer:

In standard form 0.0325 is written as 0.0325

In scientific notation it is written as:

3.25^{ - 2}

Juli2301 [7.4K]3 years ago
6 0

Answer:

3.25 ×10^-2

Step-by-step explanation:

Because you have to go back 2 to get the number you started with

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AS ALWAYS, DUE TODAY! Pls and thanks. NOTE- Legit answers only! Legit answers= Brainliest, 5.0 stars, and a Thanks. No one helpe
iren2701 [21]

Answer:

5 3/4

Step-by-step explanation:

I say this because...

9-3= 6 and 4/4 -1/4 equals 3/4 so you take the whole that was 6 and put 5 since you took 1/4 out of the whole number

7 0
3 years ago
the rectangular grassy plot 126 m by 48m has a gravel path 1.5m wide a road 2.5m wide is constructed all around it on inside of
dusya [7]

Answer:

= Sh. 2281.50

Step-by-step explanation:

Area of the path;

(126 × 2.5 ) + (2.5 × (48 - (2.5×2)

= 315 + (2.5 × 43)

= 315 + 107.5

= 422.5 m²

But; the cost of graveling is sh 5.40 per square meter

Therefore; The cost of graveling the whole path;

= 422.5 × 5.40

<u>= Sh. 2281.50</u>

6 0
4 years ago
This question is in "Real Numbers" Find: −24÷ 4 5
jolli1 [7]
Yea the answer is negative 30
4 0
3 years ago
Read 2 more answers
2. A dance floor is a square with an area of 1,444 FT(2). What are the dimensions of the dance floor?
svet-max [94.6K]

Answer:

The answer is C use a calculator

Step-by-step explanation:

not that hard lol

8 0
3 years ago
The number of text messages sent daily by a student is a poisson random variable with parameter λ=5 .in a class with 20 independ
Rudik [331]
This problem is a combination of the Poisson distribution and binomial distribution.

First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961

For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5)   or approximately
=0.00006181
7 0
4 years ago
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