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olya-2409 [2.1K]
3 years ago
6

What is the volume of the square pyramid with base edges 32 mm and slant height 34 mm?

Mathematics
1 answer:
leonid [27]3 years ago
5 0

Answer:

V = 10,240mm^3

Step-by-step explanation:

The volume of pyramid is given by the following formula:

V=\frac{1}{3}bh  (1)

b: base of the pyramid = (32mm)^2

h: height

Thus, it is necessary to find the value of h, by using the Pitagoras's theorem, one half of the base and the slant height (which forms a rectangle triangle with h):

h=\sqrt{(34)^2-(16)^2}=30mm

by replacing in (1) you obtain:

V=\frac{1}{3}(32mm)^2(30mm)=10,240\ mm^3

hence, the volume is 10240mm^3

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If Pam has $40 in her account how much does her brother have on his
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Answer:

brother has $100

Step-by-step explanation:

Pam and her brother both open savings accounts. each begin with a balance of $0. For every $2 is that Pam saves in her account her brother saves $5 in his account

P:brother =2:5

when P=40 what is brother?

2/5=40/b

times 5b both sides

2b=200

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brother has $100

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3 years ago
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Can someone help me with this
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The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

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<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

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Learn more about circle, refer:

brainly.com/question/24810873

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