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3 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

olchik [2.2K]3 years ago

6 0

Answer:

2.) undefined slope 3.) zero slope (i'm not sure what 1 and 4 are, sorry!)

Step-by-step explanation:

undefined slope has the same x-coordinate and the denominator becomes 0. it also is a vertical line. for a zero slope, it has the same y-coordinate and the numerator is 0. this is a horizontal line. *this is my first response so if i am wrong, that is embarrassing*

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Ashley has b decks of cards. Each deck has 52 cards in it. Using b, write an expression for the total number of cards Ashley has

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Answer:

b*52

Step-by-step explanation:

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2 years ago

What is 2 3 of 99kg?

ozzi

Step-by-step explanation:

$\frac{2}{3} \times \frac{99}{1} = 66 \: kg$

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3 years ago

a city parking garage charges a flat fee of %5.00 for parking, and %1.00 per hour for every hour. (parking for 0 hours is $5, pa

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3 years ago

A solid metal cube of side 1-2 cm has a mass of 15 grams.

sashaice [31]

Answer:

The mass of the second cube is about 1085.07 grams.

Step-by-step explanation:

I assume '1-2 cm' means 1.2cm here. Correct me if I am wrong and I'll edit my answer.

First, find the density of this cube:

$d=\frac{m}{v}$

where d is density, m is mass, and v is volume.

We have one of those, but we also need volume. The volume of a cube is just:

$v=a^3$

where a is the length of a side.

$\rightarrow v=1.2^3\\\rightarrow v=1.728$

The volume of this cube is 1.728cm³. Now, you can find the density;

$\rightarrow d=\frac{15}{1.728}\\\rightarrow d\approx8.6806$

The density of this material is about 8.68 grams per cubic centimeter.

Finally, you can use that density to find the mass of the other cube. Fin the volume of the second cube:

$\rightarrow v=5^3\\\rightarrow v=125$

The volume is 125cm³. Given the density and the volume, you can calculate the mass:

$\rightarrow d=\frac{m}{v}\\\rightarrow 8.6806=\frac{m}{125}\\\rightarrow 8.6806\times125=m\\\rightarrow m=1085.0694$

The mass of the second cube is about 1085.07 grams.

4 0

3 years ago

Can someone help assist me on this Honors Algebra 2 Problem? Challenge Problems #6. The distance from a point on the curve y=√x

ahrayia [7]

Answer: (0, 0) & (3, √3)

<u>Step-by-step explanation:</u>

Since we need a distance of 2, I graphed y = √x and then drew a circle at center (2, 0) and radius of 2 to see where they intersect.

The coordinates of intersection can be determined by solving a system of equations.

Equation 1: y = √x

Equation 2: (x - 2)² + y² = 2²

I will use the Substitution method with Equation 2 to solve for x:

(x - 2)² + (√x)² = 2² substituted y with √x

x² - 4x + 4 + x = 4 expanded binomial

x² - 3x + 4 = 4 added like terms

x² - 3x = 0 subtracted 4 from both sides

x(x - 3) = 0 factored

x = 0 x - 3 = 0 applied Zero Product Property

x = 3

Next, solve for y using Equation 1:

x = 0: y = √0 = 0

x = 3: y = √3

Coordinates of intersection are: (0, 0) & (3, √3)

6 0

3 years ago