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yan [13]
3 years ago
14

oday, everything at a store is on sale. The store offers a 20% discount. **NUMBERS ONLY. NO SYMBOLS.** a. The regular price of a

T-shirt is $18. What is the discount price? b. The discount price of a hat is $18. What is the regular price
Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

Discount price of T-shirt is $14.40

Regular price of hat is $22.50

Step-by-step explanation:

The regular price, without a discount, of the T-shirt is $18. Since the store offers a discount of 20%, we must remove 20% of the price.

100%-20%=80%. So, the discount price is 80% of the regular price.

18 × 80% = 14.4

So, the discount price of the T-shirt is $14.40.

The hat, on a discount of 20%, costs $18. To find the regular price, we must multiply it by the reciprocal of 80%, which is 100/80, or 1.25.

1.25 × 18 = 22.5

So, the regular price of the hat is $22.50.

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Find the GCF of the terms of the polynomial. 33x^3 + 18^6
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Your friend says 3/10 is equivalent to 10 divided by 3. Is your friend correct? Explain.
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4 0
2 years ago
The average of 16 consecutive positive integers is 30.5. What is the average of the first 8 integers of this set?
GREYUIT [131]

consecutive integers are 1 apart

16 of them can be represented as

x, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9, x+10, x+11, x+12, x+13, x+14, x+15


the average is \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15}{16}=30.5


there might be some trick to get the average of the first 8 integers only

the average of the first 8 integers would be \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7}{8}=?

how can we get \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7}{8}=? from \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15}{16}=30.5


first, let's match the denomenators (make them both 1 for ease)


multiply the first eqution by 8 to get

x+x+1+x+2+x+3+x+4+x+5+x+6+x+7=8?


multiply the 2nd equation by 16 to get

x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


notice that we can try and force the 1st equation into the 2nd equation by adding some numbers



we can already do this:


x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


[x+x+1+x+2+x+3+x+4+x+5+x+6+x+7]+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


[8?]+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


we can try to force another 8? into it

[8?]+x+7+1+x+7+2+x+7+3+x+7+4+x+7+5+x+7+6+x+7+7+x+7+8=488

[8?]+(x)+7+(1+x)+7+(2+x)+7+(3+x)+7+(4+x)+7+(5+x)+7+(6+x)+7+(7+x)+7+8=488

[8?]+(x)+7+(x+1)+7+(x+2)+7+(x+3)+7+(x+4)+7+(x+5)+7+(x+6)+7+(x+7)+7+8=488

group

[8?]+[x+x+1+x+2+x+3+x+4+x+5+x+6+x+7]+7+7+7+7+7+7+7+7+8=488

[8?]+[8?]+8(7)+8=488

16?+64=488

minus 64 from both sides

16?=424

divide both sides by 16

?=26.5


the average of the first 8 integers is 26.5


I'm not sure if there is a simpler way to do it or not

8 0
3 years ago
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