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Helga [31]
2 years ago
10

What number is not a factor of 24

Mathematics
1 answer:
nadezda [96]2 years ago
7 0
Step-by-step explanation:
5 is not the factor of 24
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My question is the picture​
AysviL [449]

Answer:

20 students

Step-by-step explanation:

You first have to add the number of students all up and you get 200.Then you do cross multiplication.

40/200 x s/100=

40x100= 4000=

200xs= 200s=

200s/200=

4000/200=

20=

5 0
2 years ago
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
3 years ago
Which arrangement shows275, 5.36, 535, and 336 in order from least to greatest?
Vadim26 [7]

Answer:

5.36,275,336,535

Step-by-step explanation:

7 0
3 years ago
Graph the hyperbola y^2/16-x^2/9=1. What type of transverse axis does it have?
gulaghasi [49]
<span>Center(0,0)
a^2=16
a=4
b^2=9

b=3
c^2=a^2+b^2=16+9=25
c=√25=5</span>
3 0
3 years ago
Helppppppppppppppppppppppppp
Advocard [28]

Answer:

$2

$18

Step-by-step explanation:

6 0
2 years ago
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