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Cerrena [4.2K]
3 years ago
10

This is for 100 Which equation represents the relationship between the x-and y-values shown in the table

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

The table isn't available to view

Step-by-step explanation:

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Solve for x 4x - 4 < 8
UNO [17]

Answer:

x < 3

Step-by-step explanation:

Yup

5 0
3 years ago
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Idk how to do this, someone please help
Mariana [72]
Take the formula: y=mx+b
m= slope
b=y-intercept

m=2
b=-1
therefore: 
y=2x-1
3 0
3 years ago
Solve for x −9x+5≤17 OR 13x+25≤−1
arsen [322]

Answer:

(-∞ 2] ∪ [-4/3 ∞ )

Step-by-step explanation:

Given compound inequality,

-9x+5\leq 17\text{ or }13x+25\leq -1

-9x\leq 12\text{ or }13x\leq -26  ( Subtraction property of inequality )

-x\leq \frac{12}{9}\text{ or }x\leq -\frac{26}{13}   ( Division property of inequality )

-x\leq \frac{4}{3}\text{ or }x\leq -2

x\geq -\frac{4}{3}\text{ or }x\leq -2   ( a < b ⇒ - a > - b )

Hence, the solution of the given inequality is,

(-∞ -2] ∪ [-4/3 ∞ )

3 0
3 years ago
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working together two mathletes solve 32 math problems in a certain amount of time how many problems will 3 mathletes solve if th
dexar [7]

If they together at the same rate for the same amount of time, they will solve 48 math problems,

From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:

  • 2 mathletes = 32 math problems

In order to determine the number of problems for 3 mathletes, this is expressed as:

  • 3 mathletes = x

DIvide both expressions:

  • 2/3 = 32/x

Cross multiply

2x = 3* 32

x = 3 * 16

x = 48math problems

Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,

Learn more on proportion here: brainly.com/question/1496357

6 0
2 years ago
I need to know question 8 I’m confused
marissa [1.9K]

Remark

Let the pigs = p

Let the chickens = c

Givens

30 heads is another way of saying that there were 30 creatures in the barnyard. In addition each chicken has 2 legs and each pig has 4

c + p = 30

2C + 4P = 100       (2) Divide (2) by 2

C + 2P = 50           (3)  Subtract (1) from (3)

<u>C + P    = 30</u>

       P  = 20

So there were 20 pigs.

3 0
3 years ago
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