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Diano4ka-milaya [45]
3 years ago
7

Hey that weighs two puppies the small puppy weighs 4 1/2 pounds the last puppy weighs four two thirds times as much as the small

puppy how much does the large puppy weigh
Mathematics
2 answers:
Marina86 [1]3 years ago
7 0
So I hope this helps

You need to multiply

9/2*14/3=126/6

So make that a improper fraction

21 pounds the large dog weighs
Alika [10]3 years ago
4 0
9/2*14/3=126/6 = 21 lbs 
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Abbie babysits on the weekends. She charges $10 for the first hour and $6 for each
Dvinal [7]

Answer:

5 hours

Step-by-step explanation:

34-10(first hour) is 24

24/6(price per additonal hour)=4

so  theres four additional hours and the one OG hour so its 5 hours total

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3 years ago
Express the sum or difference as a product: cos 4x - cos 6x
Jobisdone [24]
Cos -2x or -cos2x, it's the difference.
3 0
3 years ago
Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (
Fudgin [204]
A.

\displaystyle\frac1a-\frac1h=\frac1h-\frac1b
\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}
\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}
\implies\displaystyle\frac{h-a}{b-h}=\frac ab

b.

\displaystyle h=\frac{2ab}{a+b}
\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}
\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}
\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}
\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}
\displaystyle\implies\frac{h-a}{b-h}=\frac ab

The other direction can be proved by following the manipulations in the reverse order.
7 0
3 years ago
What is .93 divided to 19.43 to the nearest whole number
Brrunno [24]
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5 0
3 years ago
-1 1/3 divided by 2 2/5
Crazy boy [7]

Answer:

-5/12

Step-by-step explanation:

-1 times 1 is -1 so -1/3

2 times 2 is 4 so 4/5

-1/3 divided by 4/5

to make it easier we will write like this:

-1/3 times 5/4

-1 times 5=-5

3 times 4=12

so the final answer is  -5/12

HOPE IT HELP U

8 0
4 years ago
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