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2 years ago

Hurry plsss Plsssss

Mathematics

1 answer:

svetlana [45]2 years ago

4 0

Answer:

B is the correct answer as it qualifies for all the answers correctly.

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Albert’s father is 24 years older than Albert. In 8 years, his father will be twice as old as Albert. How old is Albert now? How

kondor19780726 [428]

Answer:

Albert is 24. Albert's father is 48

Step-by-step explanation:

3 0

2 years ago

Using long division to find the quotient and remainder 4x^4+2x^2-2 divided by x^2+2

emmasim [6.3K]

4x² -6
__________________
x²+2 l 4x^4 +2x² -2
l 4x^4 +8x²
--------------------
-6x² -2
-6x² -12
---------------
10

so the answer is $(4x^2-6) \frac{10}{x^2+2}$

8 0

3 years ago

What is the measure of the missing angle

Oduvanchick [21]

Answer:

40 degrees!

Step-by-step explanation:

95 + 45 = 140

180 - 140 = 40

8 0

2 years ago

A ball of mass 0.4 kg flies through the air at low speed, so that air resistance is negligible. What is the net force acting on

arsen [322]

Answer:

-3.92 N

Step-by-step explanation:

We are given that

Mass of ball=0.4 kg

Acceleration due to gravity= $-9.8m/s^2$

Because the ball flies against to gravity

We have to find the net force acting on the ball while it is in motion.

We know that when there is no air resistance then the net force acts on the ball is equal to weight of ball.

Net force,F =mg

Substitute the values then we get

$F=0.4(-9.8)$

$F=-3.92N$

Hence, the net force acting on the ball while it is on motion=-3.92 N

6 0

2 years ago

If f(x) = x + 4 and g(x)=x^2-1, what is m(g o f)(x)?

Andreas93 [3]

Until now, given a function f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:

Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and

let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.

Find (i) f (1), (ii) g(–1), and (iii) (g o f )(1).

(i) This type of exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:

8 0

2 years ago

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