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nadya68 [22]
2 years ago
8

How can you represent the repeating decimal 0.3 (0.333333) as a fraction?

Mathematics
1 answer:
Tems11 [23]2 years ago
5 0
<h3>when you write 0.33333333 in a calculator and convert it to fraction using the a b/c button you should get 1/3 as an answer</h3>

<h3>another method is </h3>

  • Step 1: Write down the decimal divided by 1

  • Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)

  • Step 3: Simplify (or reduce) the fraction

refer to picture above plzz***

hope that helps !

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Determine if the two triangles are congruent. If so, select the appropriate congruence postulate. If not, select the reason why.
morpeh [17]

Answer:

Asa

Step-by-step explanation:

Because if u look left to right on one triangle there is a angle and in between they have a com on line and on the right theres another angle so There for it’s angle side angle

4 0
2 years ago
Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.
Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0
3 years ago
Round the fraction or mixed number to the nearest 1/2 ( each one)
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1, 4, 100 1/2, 4 1/2, 5
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5. Let A = (x, y), B = {1,2). Find the Cartesian products of A and B: A x B? (Hint: the result will be a set of pairs (a, b) whe
hichkok12 [17]

Answer: A x B = {(x,1), (x,2), (y,1), (y,2)}

Step-by-step explanation:

The Cartesian product of any two sets M and N is the set of all possible ordered pairs such that the elements of M are first values and the elements of N are the second values.

The Cartesian product of sets M and N is denoted by M × N.

For Example : M = {x,y} and N={a,b}

Then , M × N ={(x,a), (x,b), (y,a), (y,b)}

Given : Let A = {x, y}, B = {1,2}

Then , the Cartesian products of A and B will be :

A x B = {(x,1), (x,2), (y,1), (y,2)}

Hence, the Cartesian products of A and B = A x B = {(x,1), (x,2), (y,1), (y,2)}

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Answer: 255 calories hope this helps :)

Step-by-step explanation:

8 0
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