B)
1.80c +3h = 288.60
c=1 -2h
1) Gathering the data
Cold lunch (c) : $1.80
Hot lunch (h) : $3.00
Total $288.60
c = 1 -2h
2) Let's set up a system of equations, based on that
1.80c +3h = 288.60 <em>This equation relates the cost of those lunches</em>
c=1 -2h <em>The relationship between the number of lunches</em>
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Examining the options:
3) We can state that the answer is B
Answer:
8x^2-2x+8
Step-by-step explanation:
2x^2−3x+9)+(6x^2+x−1)
Combine like terms
2x^2 +6x^2 -3x+x +9-1
8x^2-2x+8
Answer: There are 5 nickels and 10 quarters.
Step-by-step explanation:
Let x = Nickels , y= Quarters.
Then x+y = 15
⇒ y=15-x (i)
1 nickel = 5 cents , 1 quarter = 25 cents
$2.75 = 275 cents [ 1 dollar = 100 cents ]
Then, 5x+25y= 275 (ii)
Substitute value of y from (i)
5x+25 (15-x)=275
⇒ 5x + 375 - 25x =275
⇒ -20x= 275-375
⇒ -20x= -100
⇒ x = 5 [divide both sides by -20]
Put this in (i) , we get y= 15-5=10
Hence, there are 5 nickels and 10 quarters.